Second moment of a Gaussian-kernel stochastic integral

Let WtW_t be a standard Brownian motion. Find the variance of X=∫02t eWt2/8 dWtX = \displaystyle\int_0^2 \sqrt{t}\,e^{W_t^2/8}\,dW_t.

Show hints (2)+
  1. Itô isometry: Var⁡(X)=E[∫02t eWt2/4 dt]=∫02t E[eWt2/4] dt\operatorname{Var}(X)=\mathbb{E}[\int_0^2 t\,e^{W_t^2/4}\,dt]=\int_0^2 t\,\mathbb{E}[e^{W_t^2/4}]\,dt.
  2. E[eWt2/4]=(1−t/2)−1/2\mathbb{E}[e^{W_t^2/4}]=(1-t/2)^{-1/2}; then ∫02t(1−t/2)−1/2dt=163\int_0^2 t(1-t/2)^{-1/2}dt=\tfrac{16}{3}.

Answer

Reveal answer →

5.3333 (± 0.02)

Create a free account to see the full worked solution and track your progress.

Interview format: Market Maker, Hedge Fund Quant

Related questions