A mixed second partial derivative

EasyCalculus~3m

For f(x,y)=x2y2+x3yf(x,y)=x^2 y^2 + x^3 y, evaluate the mixed second partial 2fxy\dfrac{\partial^2 f}{\partial x\,\partial y} at the point (x,y)=(1,2)(x,y)=(1,2).

Show hints (2)+
  1. Differentiate first in yy (hold xx fixed), then in xx (hold yy fixed).
  2. f/y=2x2y+x3\partial f/\partial y = 2x^2y + x^3; now take /x\partial/\partial x, then plug in (1,2)(1,2).

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