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A limit by L'Hôpital

EasyCalculus~3m

Evaluate lim⁡x→0+x2ln⁡x\displaystyle\lim_{x\to 0^+} x^2 \ln x.

Show hints (2)+
  1. The polynomial factor wins over the logarithm.
  2. Rewrite so L'Hôpital applies.

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