Where the slope is steepest downhill

MediumCalculus~3m

For $f(x)=x^3 - 6x^2 + 5$ , the graph decreases over some interval. What is the most negative value the slope $f'(x)$ attains (i.e. the minimum of $f'$ )?

Show hints (2)+

You're minimising the slope $f'$ , so set $(f')' = f'' = 0$ .
$f''=6x-12=0$ at $x=2$ ; evaluate $f'(2)$ .

Answer

Reveal answer →

-12

Create a free account to see the full worked solution and track your progress.

Create a free account

Interview format: Trading Aptitude Tests, Prop Trading

Where the slope is steepest downhill

Answer

Related questions