Leibniz rule derivative at x = 1

MediumCalculus~5m

Let g(x)=∫0x2e−t dtg(x)=\displaystyle\int_0^{x^2} e^{-t}\,dt. Compute g′(1)g'(1). (to 3 decimals)

Show hints (2)+
  1. Differentiate the upper limit via the chain rule.
  2. g′(x)=e−x2⋅ddx(x2)g'(x)=e^{-x^2}\cdot\frac{d}{dx}(x^2).

Answer

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0.736 (± 0.005)

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