Arc length of a curve

MediumCalculus~4m

Find the arc length of the curve y=23x3/2y = \tfrac{2}{3}x^{3/2} from x=0x=0 to x=3x=3. (to 3 decimals)

Show hints (2)+
  1. L=∫ab1+(y′)2 dxL=\int_a^b\sqrt{1+(y')^2}\,dx; here y′=xy'=\sqrt x so the radical becomes 1+x\sqrt{1+x}.
  2. Antiderivative 23(1+x)3/2\tfrac23(1+x)^{3/2}; note 43/2=84^{3/2}=8.

Answer

Reveal answer →

4.667 (± 0.005)

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