More heads than tails in six flips

A fair coin is flipped 6 times. What is the probability of getting strictly more heads than tails? Give a decimal to four places.

Show hints (2)+

Six flips can tie (3–3), so it isn't $\tfrac12$ .
$P(\text{more heads}) = (1 - P(\text{tie}))/2$ ; find $P(\text{3-3})=\binom{6}{3}/64$ .

Answer

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0.3438 (± 0.001)

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Asked at: Probability & Market-Making, Options Market-Making