Length of a vector difference

Two vectors satisfy a=5\|a\| = 5, b=3\|b\| = 3, and a+b=7\|a + b\| = 7. Find ab\|a - b\|. (to 4 decimals)

Show hints (2)+
  1. Expand a+b2=a2+2(ab)+b2\|a+b\|^2 = \|a\|^2 + 2(a\cdot b) + \|b\|^2 to solve for aba\cdot b first.
  2. Then ab2=a22(ab)+b2\|a-b\|^2 = \|a\|^2 - 2(a\cdot b) + \|b\|^2 - flip the sign on the cross term.

Answer

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4.3589 (± 0.001)

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Asked at: Timed Mental-Math & Sequences, Game-Based Aptitude

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