Fair price of a higher-die contract

You and a counterparty each roll one fair die. A contract pays you $12 if your die is strictly higher than theirs, and nothing on a tie or a loss. What is the fair value of this contract (its expected payout, in dollars)?

Show hints (2)+
  1. By symmetry, P(you higher)=P(they higher)P(\text{you higher}) = P(\text{they higher}); only the tie breaks the tie.
  2. P(tie)=16P(\text{tie}) = \tfrac16, so P(win)=11/62=512P(\text{win}) = \tfrac{1 - 1/6}{2} = \tfrac{5}{12}.

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Asked at: Options Market-Making, ETF Market-Making

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