Variance of the longer piece

A 11-metre rope is cut at a single uniformly random point, giving two pieces. Let LL be the length of the longer piece. Compute Var(L)\operatorname{Var}(L).

Show hints (2)+
  1. L=max(U,1U)L=\max(U,1-U) lives in [12,1][\tfrac12,1]. Find its CDF there.
  2. It's Uniform(12,1)\text{Uniform}(\tfrac12,1); variance of a length-12\tfrac12 uniform is (1/2)2/12(1/2)^2/12.

Answer

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0.0208 (± 0.001)

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Asked at: IMC, SIG

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