Counting fives before a four and a six

A fair 66-sided die is rolled repeatedly until both a 44 and a 66 have appeared (at least one of each). What is the probability that exactly two 55s are rolled during this process?

Show hints (2)+
  1. Rolls of 1,2,31,2,3 don't matter - restrict to {4,5,6}\{4,5,6\} rolls, each with probability 1/31/3.
  2. Split the 55-count into phase 1 (before the first of {4,6}\{4,6\}) and phase 2 (waiting for the second); the two are independent. Then sum over F1+F2=2F_1+F_2=2.

Answer

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0.1759 (± 0.002)

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Asked at: Jane Street, Citadel

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