Russian roulette, re-spun

MediumProbability Conditional Probability & Expectation~6m

A 6-chamber revolver holds 1 bullet. Two players alternate pulling the trigger, re-spinning the cylinder before every pull. What is the probability that the player who goes first is the one who gets shot? (to 3 decimals)

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Re-spinning makes each pull independent (1/6).
Set up $p = 1/6 + (5/6)(1-p)$ .

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0.5455 (± 0.005)

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Russian roulette, re-spun

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