Rolling until two rolls differ by two

A fair 66-sided die is rolled repeatedly. What is the expected number of rolls until two consecutive rolls differ by exactly 22 (i.e. ∣current−previous∣=2|{\text{current}} - {\text{previous}}| = 2)?

Show hints (2)+
  1. Let eve_v be expected extra rolls given last face vv; how many faces are exactly 22 away from vv? (One for 1,2,5,61,2,5,6; two for 3,43,4.)
  2. Solve the small symmetric system (e1=e2=5e_1=e_2=5, e3=4e_3=4), then E=1+16∑ev\mathbb{E}=1+\tfrac16\sum e_v.

Answer

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5.6667 (± 0.01)

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