How large can the off-diagonal be?

The symmetric matrix (5bb2)\begin{pmatrix} 5 & b \\ b & 2 \end{pmatrix} is positive definite exactly when b<b|b| < b^* for some threshold bb^*. Find bb^*. (to 4 decimals)

Show hints (2)+
  1. Sylvester: a symmetric matrix is PD iff all leading principal minors are positive.
  2. The binding one is det=10b2>0\det = 10 - b^2 > 0, so b<10|b| < \sqrt{10}.

Answer

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3.1623 (± 0.001)

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Asked at: Citadel, Two Sigma

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