Eigenvalue of a matrix power

If λ=2\lambda = 2 is an eigenvalue of AA, what is the corresponding eigenvalue of A5A^5 (same eigenvector)?

Show hints (1)+
  1. $A^k v = \lambda^k v$.

Answer

Reveal answer →

32

Want the full step-by-step worked solution? It's part of Premium — along with a worked solution for every question in the bank.

Asked at: Jane Street, Two Sigma

Related questions