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The higher die shows a four

EasyProbability~3m

You roll two fair 66-sided dice. What is the probability that the larger of the two values is exactly 44?

Show hints (2)+
  1. P(max⁡=4)=P(both≤4)−P(both≤3)\mathbb{P}(\max=4)=\mathbb{P}(\text{both}\le4)-\mathbb{P}(\text{both}\le3).
  2. That's (4/6)2−(3/6)2(4/6)^2-(3/6)^2.

Answer

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0.1944 (± 0.001)

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