Eigenvalues of a 2×2 matrix

The matrix (5274)\begin{pmatrix} -5 & 2 \\ -7 & 4 \end{pmatrix} has two eigenvalues aa and bb. Compute a2+b2a^2 + b^2.

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  1. Eigenvalues solve λ2(tr)λ+det=0\lambda^2-(\operatorname{tr})\lambda+\det=0; here tr=1\operatorname{tr}=-1, det=6\det=-6.
  2. λ=2,3\lambda=2,-3; or use a2+b2=(tr)22det=1+12a^2+b^2=(\operatorname{tr})^2-2\det=1+12.

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Asked at: Jane Street, Two Sigma

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