A Cholesky diagonal entry

The symmetric positive-definite matrix A=(46625)A=\begin{pmatrix} 4 & 6 \\ 6 & 25 \end{pmatrix} factors as A=LLA = LL^\top with LL lower-triangular and positive diagonal. Compute the bottom-right entry L22L_{22}. (to 4 decimals)

Show hints (2)+
  1. Match LLLL^\top to AA entry by entry: L11=4L_{11}=\sqrt{4}, then L21=6/L11L_{21}=6/L_{11}.
  2. L22=A22L212=259L_{22}=\sqrt{A_{22} - L_{21}^2}=\sqrt{25-9} — subtract the earlier column's contribution.

Answer

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4 (± 0.001)

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Asked at: DRW, Two Sigma

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