Multiplications saved by Horner's method

Consider evaluating the degree-$6$ polynomial $p(x)=2x^6 - 3x^5 + x^4 + 4x^3 - x^2 + 5x - 1$ at one value of $x$. The naive method first forms the powers $x^2, x^3, \ldots, x^6$ by one multiplication each (reusing the previous power), then multiplies each of the $6$ non-constant terms by its coefficient. Horner's nested scheme $p(x)=(\cdots((a_6 x + a_5)x + a_4)x + \cdots)x + a_0$ uses one multiply per nesting layer. How many fewer multiplications does Horner use than the naive method?