Covariance of summed Brownian motions

Let B1,B2,B3B_1, B_2, B_3 be independent standard Brownian motions. Compute Cov(B1(1)+B2(1), B2(2)+B3(2))\operatorname{Cov}\big(B_1(1) + B_2(1),\ B_2(2) + B_3(2)\big).

Show hints (2)+
  1. Expand bilinearly; covariances between different (independent) Brownian motions are 00.
  2. Only B2B_2 is shared: Cov(B2(1),B2(2))=min(1,2)=1\operatorname{Cov}(B_2(1),B_2(2))=\min(1,2)=1.

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Asked at: Citadel, Two Sigma

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