Variance of a Brownian combination

W(t)W(t) is a standard Brownian motion, and W(5)W(5) and W(2)W(2) are read off the same path. What is Var ⁣(W(5)2W(2))\operatorname{Var}\!\big(W(5) - 2\,W(2)\big)?

Show hints (2)+
  1. W(5)W(5) and W(2)W(2) are dependent — split W(5)=W(2)+(W(5)W(2))W(5)=W(2)+(W(5)-W(2)) into independent pieces.
  2. Then variances of the independent terms add, coefficients squared: 123+(1)221^2\cdot 3 + (-1)^2\cdot 2.

Answer

Reveal answer →

5

Want the full step-by-step worked solution? It's part of Premium — along with a worked solution for every question in the bank.

Asked at: Citadel, Two Sigma

Related questions