Variance of a Brownian combination

W(t)W(t) is a standard Brownian motion, and W(5)W(5) and W(2)W(2) are read off the same path. What is Var⁡ ⁣(W(5)−2 W(2))\operatorname{Var}\!\big(W(5) - 2\,W(2)\big)?

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  1. W(5)W(5) and W(2)W(2) are dependent - split W(5)=W(2)+(W(5)−W(2))W(5)=W(2)+(W(5)-W(2)) into independent pieces.
  2. Then variances of the independent terms add, coefficients squared: 12⋅3+(−1)2⋅21^2\cdot 3 + (-1)^2\cdot 2.

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